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tinboiling point = 2.270×103 °CHvap(2.270×103 °C) = 1.939×103 J/gmelting point = 232.0 °CHfus(232.0 °C) = 59.60 J/gspecific heat solid = 0.2260 J/g°Cspecific heat liquid = 0.2430 J/g°C46.70tin638.027.0Report the answer as a positive number._______ kJ